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x^2-4800x-640=0
a = 1; b = -4800; c = -640;
Δ = b2-4ac
Δ = -48002-4·1·(-640)
Δ = 23042560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{23042560}=\sqrt{256*90010}=\sqrt{256}*\sqrt{90010}=16\sqrt{90010}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4800)-16\sqrt{90010}}{2*1}=\frac{4800-16\sqrt{90010}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4800)+16\sqrt{90010}}{2*1}=\frac{4800+16\sqrt{90010}}{2} $
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